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Proof step 15 from proof ac-new (previous step)

fv = sk × val, ∀ r, class1, st. newref(r, addclass(class1, fis0, st)) ↔ newref(r, st) ⊦ newref(r, addclass(class1, fv ' + fis0, st)) ↔ newref(r, st), ¬ is_indexkey(sk) ∧ sk .fs .class ≠ class1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
∀ r, class1, st. newref(r, addclass(class1, fis0, st)) ↔ newref(r, st) ⊦ newref(r, addclass(class1, (sk × val) ' + fis0, st)) ↔ newref(r, st), ¬ is_indexkey(sk) ∧ sk .fs .class ≠ class1

Rule argument

[emptyarg]

Additional information

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