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Proof step 23 from proof ac-new (previous step)

fv = sk × val, is_fskey(sk), ∀ r, class1, st. newref(r, addclass(class1, fis0, st)) ↔ newref(r, st) ⊦ sk .fs .class = class1, newref(r, addclass(class1, fis0, st)) ↔ newref(r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
is_fskey(sk), ∀ r, class1, st. newref(r, addclass(class1, fis0, st)) ↔ newref(r, st) ⊦ sk .fs .class = class1, newref(r, addclass(class1, fis0, st)) ↔ newref(r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]