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Proof step 10 from proof ac-okclass (conclusion)

⊦ okclass(refval(r0), class1, addclass(class0, fis, st)) ↔ okclass(refval(r0), class1, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ okclass(val, class1, st) ↔ reftypep(val, st) ∧ (val .refval ≠ jvmref → val .refval -- _type ∈ st ∧ st[val .refval -- _type] = typeval(mkclasstype(class1)))
Proof step 9:
⊦ reftypep(refval(r0), addclass(class0, fis, st)) ∧ ( refval(r0) .refval ≠ jvmref → refval(r0) .refval -- _type ∈ addclass(class0, fis, st) ∧ (addclass(class0, fis, st)[refval(r0) .refval -- _type]) = typeval(mkclasstype(class1))) ↔ okclass(refval(r0), class1, st)

Rule argument

[speclemmaarg: , okclass(val, class1, st) ↔ reftypep(val, st) ∧ ( val .refval ≠ jvmref → val .refval -- _type ∈ st ∧ st[val .refval -- _type] = typeval(mkclasstype(class1))) ,[st, class1, val] → [addclass(class0, fis, st), class1, refval(r0)] ,F ,okfuns , ,okclass ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (addclass(class0, fis, st), class1, refval(r0))]]