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Proof step 15 from proof ac-refin (previous step)

¬ (is_fskey(fv .1) ∧ fv .1 .fs .class ≠ class), rk ∈ st, ∀ rk, st, class. rk ∈ st → rk ∈ addclass(class, fis0, st) ⊦ rk ∈ addclass(class, fv ' + fis0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
rk ∈ st, ∀ rk, st, class. rk ∈ st → rk ∈ addclass(class, fis0, st) ⊦ rk ∈ addclass(class, fv ' + fis0, st), ¬ is_indexkey(fv .1) ∧ fv .1 .fs .class ≠ class

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ is_fskey(sk) ↔ is_indexkey(sk)])]]