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Proof step 23 from proof ac-refin (previous step)

is_fskey(fv .1) ∧ fv .1 .fs .class ≠ class, rk ∈ st, ∀ rk, st, class. rk ∈ st → rk ∈ addclass(class, fis0, st) ⊦ rk ∈ addclass(class, fis0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
rk ∈ st, is_fskey(fv .1), ∀ rk, st, class. rk ∈ st → rk ∈ addclass(class, fis0, st) ⊦ fv .1 .fs .class = class, rk ∈ addclass(class, fis0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]