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Proof step 8 from proof ac-refin (previous step)

¬ is_indexkey((sk × val) .1), sk .fs = mkfs(class0, ty, fieldvar), rk ∈ st, ∀ rk, st, class. rk ∈ st → rk ∈ addclass(class, fis0, st) ⊦ rk ∈ addclass(class, (sk × val) ' + fis0, st), ¬ is_indexkey(sk) ∧ class0 ≠ class

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
sk .fs = mkfs(class, ty, fieldvar), is_fskey(sk), rk ∈ st, ∀ rk, st, class. rk ∈ st → rk ∈ addclass(class, fis0, st) ⊦ rk ∈ addclass(class, (sk × val) ' + fis0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ is_indexkey(sk) → ¬ is_fskey(sk)], [CSIMPSEQ : ⊦ ¬ is_indexkey(sk) ↔ is_fskey(sk)], [CSIMPSEQ : ⊦ (sk × val) .1 = sk])]]