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Proof step 14 from proof ac-refs (previous step)

¬ (is_fskey((sk × val) .1) ∧ (sk × val) .1 .fs .class ≠ class), ∀ class, st. addclass(class, fis0, st) .refs = st .refs ++ jvmref ⊦ addclass(class, (sk × val) ' + fis0, st) .refs = st .refs ++ jvmref

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
∀ class, st. addclass(class, fis0, st) .refs = st .refs ++ jvmref ⊦ addclass(class, (sk × val) ' + fis0, st) .refs = st .refs ++ jvmref, ¬ is_indexkey(sk) ∧ sk .fs .class ≠ class

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ is_fskey(sk) ↔ is_indexkey(sk)], [CSIMPSEQ : ⊦ (sk × val) .1 = sk])]]