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Proof step 20 from proof ac-shift (previous step)

fv = sk × val0, ∀ class2, class1, st, ty, fieldvar, val. class2 = class1 ∨ (addclass(class1, fis0, st)[jvmref -- mkfs(class2, ty, fieldvar) ', val]) = addclass(class1, fis0, st[jvmref -- mkfs(class2, ty, fieldvar) ', val]) ⊦ class2 = class1, (addclass(class1, fv ' + fis0, st)[jvmref -- mkfs(class2, ty, fieldvar) ', val]) = addclass(class1, fv ' + fis0, st[jvmref -- mkfs(class2, ty, fieldvar) ', val]), ¬ is_indexkey(sk) ∧ sk .fs .class ≠ class1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
∀ class2, class1, st, ty, fieldvar, val. class2 = class1 ∨ (addclass(class1, fis0, st)[jvmref -- mkfs(class2, ty, fieldvar) ', val]) = addclass(class1, fis0, st[jvmref -- mkfs(class2, ty, fieldvar) ', val]) ⊦ class2 = class1, (addclass(class1, (sk × val0) ' + fis0, st)[jvmref -- mkfs(class2, ty, fieldvar) ', val]) = addclass(class1, (sk × val0) ' + fis0, st[jvmref -- mkfs(class2, ty, fieldvar) ', val]), ¬ is_indexkey(sk) ∧ sk .fs .class ≠ class1

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]