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Proof step 18 from proof add-dupput (previous step)

sk0 ∈ fis + fis0, sk0 ∈ fis + (sk × val) ' + fis0, sk ∈ fis ⊦ (fis + (sk × val) ' + fis0)[sk0] = (fis + fis0)[sk0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
sk0 ∈ fis + fis0, sk ∈ fis ⊦ (fis + (sk × val) ' + fis0)[sk0] = (fis + fis0)[sk0]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ sk ∈ fis + fis0 → sk ∈ fis + fv ' + fis0], [CSIMPSEQ : ⊦ (fis + fis0) + fis1 = fis + fis0 + fis1])]]