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Proof step 27 from proof add-dupput (conclusion)

sk ∈ fis ⊦ addobj(r, class1, fis + (sk × val) ' + fis0, st) = addobj(r, class1, fis + fis0, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ st1 = st2 ↔ (∀ rk. (rk ∈ st1 ↔ rk ∈ st2) ∧ st1[rk] = st2[rk])
Proof step 26:
sk ∈ fis ⊦ ∀ rk. (rk ∈ addobj(r, class1, fis + (sk × val) ' + fis0, st) ↔ rk ∈ addobj(r, class1, fis + fis0, st)) ∧ (addobj(r, class1, fis + (sk × val) ' + fis0, st)[rk]) = (addobj(r, class1, fis + fis0, st)[rk])

Rule argument

[speclemmaarg: ,st1 = st2 ↔ (∀ rk. (rk ∈ st1 ↔ rk ∈ st2) ∧ st1[rk] = st2[rk]) ,[st2, st1] → [addobj(r, class1, fis + fis0, st), addobj(r, class1, fis + (sk × val) ' + fis0, st)] ,F ,store ,javastore ,Extension ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (addobj(r, class1, fis + fis0, st), addobj(r, class1, fis + (sk × val) ' + fis0, st))]]