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Proof step 3 from proof add-field-03 (conclusion)

sk ≠ sk0, sk ≠ _type ⊦ (addobj(r, class1, (sk0 × val) ', st)[r -- sk]) = st[r -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ addobj(r, class1, (sk × val) ', st) = (addobj(r, class1, [], st)[r -- sk, val])
Proof step 2:
⊦ addobj(r, class1, [], st) = st[r -- _type, typeval(mkclasstype(class1))]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r -- sk = r0 -- sk0 ↔ ¬ ¬ (r = r0 ∧ sk = sk0)], [CSIMPSEQ : ⊦ (st[rk0, val][rk]) = ((rk = rk0 ⊃ val; st[rk]))])]]