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Proof step 6 from proof add-field-same (previous step)

str ≠ str0 ⊦ (addobj(r, class, (mkfs(class0, ty0, str .field) ' × val) ' + fis, st)[r -- mkfs(class1, ty1, str0 .field) ']) = (addobj(r, class, fis, st)[r -- mkfs(class1, ty1, str0 .field) '])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ addobj(r, class1, (sk × val) ' + fis, st) = (addobj(r, class1, fis, st)[r -- sk, val])
Proof step 5:
⊦ str = str0, (addobj(r, class, fis, st)[r -- mkfs(class0, ty0, str .field) ', val][r -- mkfs(class1, ty1, str0 .field) ']) = (addobj(r, class, fis, st)[r -- mkfs(class1, ty1, str0 .field) '])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (fis + fis0) + fis1 = fis + fis0 + fis1])]]