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Proof step 8 from proof add-gins (previous step)

∀ r, class1, st, sk, val. (addobj(r, class1, fis0, st)[r -- sk, val]) = addobj(r, class1, fis0[sk, val], st) ⊦ sk = sk0, (addobj(r, class1, fis0, st)[r -- sk, val][r -- sk0, val0]) = (addobj(r, class1, fis0[sk, val], st)[r -- sk0, val0])

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 1, [extquanttermlist: (r, class1, st, sk, val) abort:F , discard:F , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, class1, st, sk, val)]]