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Proof step 2 from proof add-in-05 (conclusion)
⊦ sk ∈ fis → r -- sk ∈ addobj(r, class1, fis, st)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 1
:
sk ∈ fis ⊦ r -- sk ∈ addobj(r, class1, fis, st)
Rule argument
[emptyarg]
Additional information
[[CONCRETESIMPRULES : ()]]