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Proof step 4 from proof add-in-08 (previous step)

∀ r, sk, class, st. r -- sk ∈ addobj(r, class, fis0, st) ↔ sk ∈ fis0 ∨ sk = _type ∨ r -- sk ∈ st ⊦ sk0 = sk, r -- sk0 ∈ addobj(r, class, fis0, st) ↔ sk0 ∈ fis0 ∨ sk0 = _type ∨ r -- sk0 ∈ st

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 1, [extquanttermlist: (r, sk0, class, st) abort:F , discard:T , computed:T ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, sk0, class, st)]]