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Proof step 10 from proof add-in-09 (previous step)

∀ sk, r, class, st. sk ∈ fis0 → (addobj(r, class, fis0, st)[r -- sk]) = fis0[sk], sk ∈ fv + fis0 ⊦ (addobj(r, class, fv + fis0, st)[r -- sk]) = (fv + fis0)[sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
sk ∈ fv ' + fis0, ∀ sk, r, class, st. sk ∈ fis0 → (addobj(r, class, fis0, st)[r -- sk]) = fis0[sk] ⊦ (addobj(r, class, fv ' + fis0, st)[r -- sk]) = (fv ' + fis0)[sk]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ fv + fis = fv ' + fis])]]