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Proof step 12 from proof add-in-09 (conclusion)
⊦ sk ∈ fis → (addobj(r, class, fis, st)[r -- sk]) = fis[sk]
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 11
:
sk ∈ fis ⊦ (addobj(r, class, fis, st)[r -- sk]) = fis[sk]
Rule argument
[emptyarg]
Additional information
[[CONCRETESIMPRULES : ()]]