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Proof step 6 from proof add-isarray (conclusion)

⊦ r ≠ r0 → (is_arrayref(r, i, addobj(r0, class1, fis, st)) ↔ is_arrayref(r, i, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ r = r0, is_arrayref(r, i, addobj(r0, class1, fis, st)) ↔ is_arrayref(r, i, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]