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Proof step 6 from proof add-length (conclusion)

¬ _length ∈ fis ⊦ (addobj(r0, class, fis, st)[r -- _length]) = st[r -- _length]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ (addobj(r0, class, fis, st)[r -- _length]) = st[r -- _length], _length ∈ fis

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]