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Proof step 2 from proof add-new (conclusion)

⊦ newref(r0, addobj(r, class1, fis, st)) → r ≠ r0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ newref(r, addobj(r0, class1, fis, st)) ↔ r ≠ r0 ∧ newref(r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]