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Proof step 10 from proof add-nput-02 (previous step)

∀ r, class1, sk, val, st. addobj(r, class1, fis0 + (sk × val) ', st) = (addobj(r, class1, fis0, st)[r -- sk, val]) ∨ sk ∈ fis0 ⊦ addobj(r, class1, (fv + fis0) + (sk × val) ', st) = (addobj(r, class1, fv + fis0, st)[r -- sk, val]), sk ∈ fv + fis0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ addobj(r, class1, fv ' + fis, st) = (addobj(r, class1, fis, st)[r -- fv .1, fv .2])
Proof step 9:
∀ r, class1, sk, val, st. addobj(r, class1, fis0 + (sk × val) ', st) = (addobj(r, class1, fis0, st)[r -- sk, val]) ∨ sk ∈ fis0 ⊦ (addobj(r, class1, fis0 + (sk × val) ', st)[r -- fv .1, fv .2]) = (addobj(r, class1, fis0, st)[r -- fv .1, fv .2][r -- sk, val]), sk ∈ fv ', sk ∈ fis0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ sk ∈ fis + fis0 ↔ sk ∈ fis ∨ sk ∈ fis0], [CSIMPSEQ : ⊦ (fis + fis0) + fis1 = fis + fis0 + fis1], [CSIMPSEQ : ⊦ fv + fis = fv ' + fis])]]