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Proof step 12 from proof add-nput-02 (conclusion)

⊦ ¬ sk ∈ fis → addobj(r, class1, fis + (sk × val) ', st) = (addobj(r, class1, fis, st)[r -- sk, val])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
⊦ addobj(r, class1, fis + (sk × val) ', st) = (addobj(r, class1, fis, st)[r -- sk, val]), sk ∈ fis

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]