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Proof step 5 from proof add-nput-02 (previous step)

∀ r, class1, sk, val, st. addobj(r, class1, fis0 + (sk × val) ', st) = (addobj(r, class1, fis0, st)[r -- sk, val]) ∨ sk ∈ fis0 ⊦ (addobj(r, class1, fis0 + (sk × val) ', st)[r -- sk0, val0]) = (addobj(r, class1, fis0, st)[r -- sk, val][r -- sk0, val0]), sk = sk0, sk ∈ fis0

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 1, [extquanttermlist: (r, class1, sk, val, st) abort:F , discard:F , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, class1, sk, val, st)]]