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Proof step 7 from proof add-nput (previous step)

∀ sk, r, class1, st, val. sk = _type ∨ (addobj(r, class1, fis0, st)[r -- sk, val]) = addobj(r, class1, fis0, st[r -- sk, val]) ∨ sk ∈ fis0 ⊦ sk = _type, (addobj(r, class1, fis0, st)[r -- sk, val][r -- sk0, val0]) = (addobj(r, class1, fis0, st[r -- sk, val])[r -- sk0, val0]), sk = sk0, sk ∈ fis0

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 1, [extquanttermlist: (sk, r, class1, st, val) abort:F , discard:F , computed:F ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk, r, class1, st, val)]]