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Proof step 5 from proof add-one (conclusion)

⊦ addobj(r, class1, (sk × val) ', st) = (addobj(r, class1, [], st)[r -- sk, val])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ addobj(r, class1, [], st) = st[r -- _type, typeval(mkclasstype(class1))]
Proof step 4:
⊦ addobj(r, class1, (sk × val) ', st) = (st[r -- _type, typeval(mkclasstype(class1))][r -- sk, val])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]