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Proof step 3 from proof add-put-02 (previous step)

⊦ sk = sk0, (addobj(r, class1, fis, st)[r -- sk0, val1][r -- sk, val0]) = (addobj(r, class1, fis, st)[r -- sk, val0][r -- sk0, val1])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ rk ≠ rk0 → (st[rk0, val][rk, val0]) = (st[rk, val0][rk0, val])

Rule argument

[speclemmaarg: ,rk ≠ rk0 → (st[rk0, val][rk, val0]) = (st[rk, val0][rk0, val]) ,[val0, rk, val, rk0, st] → [val1, r -- sk0, val0, r -- sk, addobj(r, class1, fis, st)] ,F ,store ,javastore ,rew ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r -- sk = r0 -- sk0 ↔ r = r0 ∧ sk = sk0])], [EXTRATERMS : (val1, r -- sk0, val0, r -- sk, addobj(r, class1, fis, st))]]