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Proof step 19 from proof add-putbar-rew (previous step)

is_fskey(sk) ⊦ r = r0, ( r1 -- sk ∈ addobj(r0, class, fis, st) ∨ r1 = r ∧ is_indexkey(sk) ∧ i ≤ sk .index ∧ sk .index < i + n→i(# bytes) ↔ r1 -- sk ∈ addobj(r0, class, fis, putByteArray(bytes, r, i, st))) ∧ (addobj(r0, class, fis, st)[r1 -- sk]) = (addobj(r0, class, fis, putByteArray(bytes, r, i, st))[r1 -- sk])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ is_fskey(sk) ↔ (∃ fs. sk = fs ')
Proof step 18:
∃ fs. sk = fs ' ⊦ r = r0, ( r1 -- sk ∈ addobj(r0, class, fis, st) ∨ r1 = r ∧ is_indexkey(sk) ∧ i ≤ sk .index ∧ sk .index < i + n→i(# bytes) ↔ r1 -- sk ∈ addobj(r0, class, fis, putByteArray(bytes, r, i, st))) ∧ (addobj(r0, class, fis, st)[r1 -- sk]) = (addobj(r0, class, fis, putByteArray(bytes, r, i, st))[r1 -- sk])

Rule argument

[speclemmaarg: ,is_fskey(sk) ↔ (∃ fs. sk = fs ') ,[sk] → [sk] ,F ,storekey , ,ex-03 ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk)]]