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Proof step 49 from proof add-putbar-rew (previous step)

⊦ r = r0, ( rk ∈ addobj(r0, class, fis, st) ∨ rk .ref = r ∧ is_indexkey(rk .key) ∧ i ≤ rk .key .index ∧ rk .key .index < i + n→i(# bytes) ↔ rk ∈ addobj(r0, class, fis, putByteArray(bytes, r, i, st))) ∧ (putByteArray(bytes, r, i, addobj(r0, class, fis, st))[rk]) = (addobj(r0, class, fis, putByteArray(bytes, r, i, st))[rk])

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 48:
rk = r1 -- sk ⊦ r = r0, ( rk ∈ addobj(r0, class, fis, st) ∨ r1 = r ∧ is_indexkey(sk) ∧ i ≤ sk .index ∧ sk .index < i + n→i(# bytes) ↔ rk ∈ addobj(r0, class, fis, putByteArray(bytes, r, i, st))) ∧ (putByteArray(bytes, r, i, addobj(r0, class, fis, st))[rk]) = (addobj(r0, class, fis, putByteArray(bytes, r, i, st))[rk])

Rule argument

[speclemmaarg: ,r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk ,[rk, r, sk] → [rk, r1, sk] ,T ,refkey , ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk])], [EXTRATERMS : (rk, r1, sk)]]