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Proof step 52 from proof add-putbar-rew (previous step)

⊦ r = r0, putByteArray(bytes, r, i, addobj(r0, class, fis, st)) = addobj(r0, class, fis, putByteArray(bytes, r, i, st))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ st1 = st2 ↔ (∀ rk. (rk ∈ st1 ↔ rk ∈ st2) ∧ st1[rk] = st2[rk])
Proof step 51:
⊦ r = r0, ∀ rk. (rk ∈ putByteArray(bytes, r, i, addobj(r0, class, fis, st)) ↔ rk ∈ addobj(r0, class, fis, putByteArray(bytes, r, i, st))) ∧ (putByteArray(bytes, r, i, addobj(r0, class, fis, st))[rk]) = (addobj(r0, class, fis, putByteArray(bytes, r, i, st))[rk])

Rule argument

[speclemmaarg: ,st1 = st2 ↔ (∀ rk. (rk ∈ st1 ↔ rk ∈ st2) ∧ st1[rk] = st2[rk]) ,[st2, st1] → [addobj(r0, class, fis, putByteArray(bytes, r, i, st)), putByteArray(bytes, r, i, addobj(r0, class, fis, st))] ,F ,store ,javastore ,Extension ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (addobj(r0, class, fis, putByteArray(bytes, r, i, st)), putByteArray(bytes, r, i, addobj(r0, class, fis, st)))]]