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Proof step 6 from proof add-ref (previous step)

∀ r, r0, class1, st, sk. r ≠ r0 → (addobj(r, class1, fis0, st)[r0 -- sk]) = st[r0 -- sk] ⊦ r ≠ r0 → (addobj(r, class1, fv + fis0, st)[r0 -- sk]) = st[r0 -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
∀ r, r0, class1, st, sk. r ≠ r0 → (addobj(r, class1, fis0, st)[r0 -- sk]) = st[r0 -- sk] ⊦ r = r0, (addobj(r, class1, fv ' + fis0, st)[r0 -- sk]) = st[r0 -- sk]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ fv + fis = fv ' + fis])]]