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Proof step 21 from proof addclass-switch-01 (previous step)

∀ r, class, st, sk, val. r = jvmref ∨ addclass(class, fis0, st[r -- sk, val]) = (addclass(class, fis0, st)[r -- sk, val]) ⊦ r = jvmref, addclass(class, fv ' + fis0, st[r -- sk, val]) = (addclass(class, fv ' + fis0, st)[r -- sk, val]), ¬ is_indexkey(fv .1) ∧ fv .1 .fs .class ≠ class

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 20:
fv = sk0 × val0, ∀ r, class, st, sk, val. r = jvmref ∨ addclass(class, fis0, st[r -- sk, val]) = (addclass(class, fis0, st)[r -- sk, val]) ⊦ r = jvmref, addclass(class, fv ' + fis0, st[r -- sk, val]) = (addclass(class, fv ' + fis0, st)[r -- sk, val]), ¬ is_indexkey(sk0) ∧ sk0 .fs .class ≠ class

Rule argument

[speclemmaarg: ,sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val ,[fv, sk, val] → [fv, sk0, val0] ,T ,pair ,fieldinit ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val])], [EXTRATERMS : (fv, sk0, val0)]]