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Proof step 12 from proof addclass-union-sw (previous step)

⊦ (st ∪ addclass(class0, fis0, st))[rk] = (addclass(class0, fis0, st)[rk]), jvmref ∈ st

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ rk ∈ st0 → (st ∪ st0)[rk] = st0[rk]
Proof step 11:
¬ rk ∈ addclass(class0, fis0, st) ⊦ (st ∪ addclass(class0, fis0, st))[rk] = (addclass(class0, fis0, st)[rk]), jvmref ∈ st

Rule argument

[speclemmaarg: ,rk ∈ st0 → (st ∪ st0)[rk] = st0[rk] ,[rk, st0, st] → [rk, addclass(class0, fis0, st), st] ,F ,storefunsx , ,union-at-right-01 ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (rk, addclass(class0, fis0, st), st)]]