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Proof step 65 from proof addobj-addclass-sw (previous step)

⊦ r = jvmref, (r0 -- sk ∈ addobj(r, class, fis, addclass(class0, fis0, st)) ↔ r0 -- sk ∈ addclass(class0, fis0, addobj(r, class, fis, st))) ∧ (addobj(r, class, fis, addclass(class0, fis0, st))[r0 -- sk]) = (addclass(class0, fis0, addobj(r, class, fis, st))[r0 -- sk])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ r ≠ r0 → (r -- sk ∈ addobj(r0, class1, fis, st) ↔ r -- sk ∈ st)
Proof step 19:
¬ r0 ≠ r ⊦ r = jvmref, (r0 -- sk ∈ addobj(r, class, fis, addclass(class0, fis0, st)) ↔ r0 -- sk ∈ addclass(class0, fis0, addobj(r, class, fis, st))) ∧ (addobj(r, class, fis, addclass(class0, fis0, st))[r0 -- sk]) = (addclass(class0, fis0, addobj(r, class, fis, st))[r0 -- sk])
Proof step 64:
r0 ≠ r ⊦ r = jvmref, (r0 -- sk ∈ addclass(class0, fis0, st) ↔ r0 -- sk ∈ addclass(class0, fis0, addobj(r, class, fis, st))) ∧ (addobj(r, class, fis, addclass(class0, fis0, st))[r0 -- sk]) = (addclass(class0, fis0, addobj(r, class, fis, st))[r0 -- sk])

Rule argument

[crewrite-arg: add-in-04 , F , [st, fis, class1, r0, sk, r] → [addclass(class0, fis0, st), fis, class, r, sk, r0] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (addclass(class0, fis0, st), fis, class, r, sk, r0)]]