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Proof step 14 from proof addobj-addobj-switch (previous step)

⊦ r = r0, (addobj(r, class, fis, addobj(r0, class0, fis0, st))[r -- sk]) = (addobj(r, class, fis, st)[r -- sk])

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[crewrite-arg: add-in-09 , F , [sk, st, fis, class, r] → [sk, addobj(r0, class0, fis0, st), fis, class, r] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk, addobj(r0, class0, fis0, st), fis, class, r)]]