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Proof step 25 from proof addobj-addobj-switch (previous step)

⊦ (addobj(r0, class0, fis0, st)[r0 -- sk]) = (addobj(r0, class0, fis0, addobj(r, class, fis, st))[r0 -- sk]), r0 = r, sk ∈ fis0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

[crewrite-arg: add-notin , F , [sk, st, fis, class, r] → [sk, st, fis0, class0, r0] ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ typeval(ty) = typeval(ty0) ↔ ty = ty0])], [EXTRATERMS : (sk, st, fis0, class0, r0)]]