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Proof step 38 from proof addobj-addobj-switch (conclusion)

⊦ r ≠ r0 → addobj(r, class, fis, addobj(r0, class0, fis0, st)) = addobj(r0, class0, fis0, addobj(r, class, fis, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 37:
⊦ r = r0, addobj(r, class, fis, addobj(r0, class0, fis0, st)) = addobj(r0, class0, fis0, addobj(r, class, fis, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]