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Proof step 2 from proof addobj-at-03 (previous step)

⊦ r = r0, (addobj(r0, class, sks, st)[r -- sk]) = st[r -- sk]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ r ≠ r0 ∨ ¬ sk ∈ sks ∧ sk ≠ _type → (addobj(r0, class, sks, st)[r -- sk]) = st[r -- sk]

Rule argument

[crewrite-arg: addobj-at-01 , F , [sk, r, st, sks, class, r0] → [sk, r, st, sks, class, r0] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk, r, st, sks, class, r0)]]