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Proof step 2 from proof addobj-at-other-01 (previous step)

⊦ r = r0, (addobj(r, class, fis, st)[r0 -- (sk ' + sk0 ')]) = (addobj(r, class, fis, st)[st[r0 -- sk] .refval -- sk0])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ r ≠ r0 ∧ sks ≠ [] → (addobj(r, class, fis, st)[r0 -- (sk ' + sks)]) = (addobj(r, class, fis, st)[st[r0 -- sk] .refval -- sks])

Rule argument

[crewrite-arg: addobj-at-other , F , [sks, sk, r0, st, fis, class, r] → [sk0 ', sk, r0, st, fis, class, r] ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ st[r -- sk '] = st[r -- sk]], [CSIMPSEQ : ⊦ sk ' ≠ []])], [EXTRATERMS : (sk0 ', sk, r0, st, fis, class, r)]]