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Proof step 28 from proof addobj-delsw (previous step)

⊦ r = r0, ∀ rk. (rk ∈ addobj(r0, class, fis, st) -- r ↔ rk ∈ addobj(r0, class, fis, st -- r)) ∧ (addobj(r0, class, fis, st) -- r)[rk] = (addobj(r0, class, fis, st -- r)[rk])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
⊦ r = r0, (rk ∈ addobj(r0, class, fis, st) -- r ↔ rk ∈ addobj(r0, class, fis, st -- r)) ∧ (addobj(r0, class, fis, st) -- r)[rk] = (addobj(r0, class, fis, st -- r)[rk])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]