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Proof step 2 from proof addobj-in-01 (previous step)

⊦ sk = _type, r -- sk ∈ addobj(r0, class, sks, st) ↔ r -- sk ∈ st, sk ∈ sks

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ r ≠ r0 ∨ ¬ sk ∈ sks ∧ sk ≠ _type → (r -- sk ∈ addobj(r0, class, sks, st) ↔ r -- sk ∈ st)

Rule argument

[crewrite-arg: addobj-in-02 , F , [st, sks, class, r0, sk, r] → [st, sks, class, r0, sk, r] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, sks, class, r0, sk, r)]]