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Proof step 2 from proof addobj-put-switch (previous step)

⊦ r = r0, addobj(r, class1, fis, st[r0 -- sk, val]) = (addobj(r, class1, fis, st)[r0 -- sk, val])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ r ≠ r0 → (addobj(r, class1, fis, st)[r0 -- sk, val]) = addobj(r, class1, fis, st[r0 -- sk, val])

Rule argument

[crewrite-arg: ao-put , F , [val, sk, r0, st, fis, class1, r] → [val, sk, r0, st, fis, class1, r] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (val, sk, r0, st, fis, class1, r)]]