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Proof step 5 from proof addobj-subset (previous step)

newref(r, st), r0 -- sk ∈ st ⊦ r = jvmref, r0 -- sk ∈ addobj(r, class, instfields(class), st) ∧ st[r0 -- sk] = (addobj(r, class, instfields(class), st)[r0 -- sk])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
newref(r, st), r0 -- sk ∈ st, r0 ∈ st ⊦ r = jvmref, r0 -- sk ∈ addobj(r, class, instfields(class), st) ∧ st[r0 -- sk] = (addobj(r, class, instfields(class), st)[r0 -- sk])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ r -- sk ∈ st → r ∈ st])]]