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Proof step 15 from proof addobj-union-rew (previous step)

sk ∈ fis, newref(r0, st0), newref(r0, st) ⊦ fis[sk] = (st ∪ addobj(r0, class, fis, st0))[r0 -- sk], r0 = jvmref

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 12:
⊦ rk ∈ st0 → (st ∪ st0)[rk] = st0[rk]
Proof step 13:
sk ∈ fis ⊦ r -- sk ∈ addobj(r, class1, fis, st)
Proof step 14:
⊦ sk ∈ fis → (addobj(r, class, fis, st)[r -- sk]) = fis[sk]

Rule argument

[speclemmaarg: ,rk ∈ st0 → (st ∪ st0)[rk] = st0[rk] ,[rk, st0, st] → [r0 -- sk, addobj(r0, class, fis, st0), st] ,F ,storefunsx , ,union-at-right-01 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ rk ∈ st0 → (st ∪ st0)[rk] = st[rk]])], [EXTRATERMS : (r0 -- sk, addobj(r0, class, fis, st0), st)]]