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Proof step 24 from proof addobj-union-rew (previous step)

¬ sk ∈ fis ∧ sk ≠ _type, newref(r0, st), newref(r0, st0) ⊦ r0 = jvmref, (st ∪ st0)[r0 -- sk] = (st ∪ addobj(r0, class, fis, st0))[r0 -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
newref(r0, st0), newref(r0, st) ⊦ sk = _type, (st ∪ st0)[r0 -- sk] = (st ∪ addobj(r0, class, fis, st0))[r0 -- sk], r0 = jvmref, sk ∈ fis

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]