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Proof step 14 from proof addobj-union (previous step)

¬ sk ∈ fis ∧ sk ≠ _type, newref(r, st0), newref(r, st) ⊦ r = jvmref, (addobj(r, class, fis, st) ∪ st0)[r -- sk] = (st ∪ st0)[r -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
newref(r, st), newref(r, st0) ⊦ sk = _type, (addobj(r, class, fis, st) ∪ st0)[r -- sk] = (st ∪ st0)[r -- sk], r = jvmref, sk ∈ fis

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]