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Proof step 16 from proof addobj-union (previous step)

¬ r0 ≠ r, newref(r, st0), newref(r, st) ⊦ r = jvmref, (r0 -- sk ∈ addobj(r, class, fis, st) ∪ st0 ↔ r0 -- sk ∈ addobj(r, class, fis, st ∪ st0)) ∧ (addobj(r, class, fis, st) ∪ st0)[r0 -- sk] = (addobj(r, class, fis, st ∪ st0)[r0 -- sk])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ r -- sk ∈ addobj(r, class, fis, st) ↔ ¬ ¬ (sk ∈ fis ∨ sk = _type ∨ r -- sk ∈ st)
Proof step 15:
newref(r, st0), newref(r, st) ⊦ r = jvmref, (addobj(r, class, fis, st) ∪ st0)[r -- sk] = (addobj(r, class, fis, st ∪ st0)[r -- sk])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ rk ∈ st ∪ st0 ↔ rk ∈ st ∨ rk ∈ st0])]]