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Proof step 25 from proof addobj-union (previous step)

newref(r, st), newref(r, st0) ⊦ ∀ rk. (rk ∈ addobj(r, class, fis, st) ∪ st0 ↔ rk ∈ addobj(r, class, fis, st ∪ st0)) ∧ (addobj(r, class, fis, st) ∪ st0)[rk] = (addobj(r, class, fis, st ∪ st0)[rk]), r = jvmref

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
newref(r, st0), newref(r, st) ⊦ r = jvmref, (rk ∈ addobj(r, class, fis, st) ∪ st0 ↔ rk ∈ addobj(r, class, fis, st ∪ st0)) ∧ (addobj(r, class, fis, st) ∪ st0)[rk] = (addobj(r, class, fis, st ∪ st0)[rk])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]