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Proof step 11 from proof del-addobj (previous step)

¬ r0 ∈ addobj(r0, class, fis, st) -- r0 ∧ (∀ r1, sk. r0 ≠ r1 → (r1 -- sk ∈ addobj(r0, class, fis, st) ↔ r1 -- sk ∈ addobj(r0, class, fis, st) -- r0) ∧ (addobj(r0, class, fis, st)[r1 -- sk]) = (addobj(r0, class, fis, st) -- r0)[r1 -- sk]), newref(r0, st) ⊦ (addobj(r0, class, fis, st) -- r0)[r0 -- sk] = st[r0 -- sk], r0 = jvmref

User applied rule prop simplification

And obtained the following new goals

Proof step 10:
¬ r0 ∈ addobj(r0, class, fis, st) -- r0, ∀ r1, sk. r0 ≠ r1 → (r1 -- sk ∈ addobj(r0, class, fis, st) ↔ r1 -- sk ∈ addobj(r0, class, fis, st) -- r0) ∧ (addobj(r0, class, fis, st)[r1 -- sk]) = (addobj(r0, class, fis, st) -- r0)[r1 -- sk], newref(r0, st) ⊦ (addobj(r0, class, fis, st) -- r0)[r0 -- sk] = st[r0 -- sk], r0 = jvmref

Rule argument

[fmapos-arg: pos: left 1]

Additional information

[[CONCRETESIMPRULES : ()]]