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Proof step 18 from proof del-addobj (previous step)

newref(r, st) ⊦ r = jvmref, (r0 -- sk ∈ addobj(r, class, fis, st) -- r ↔ r0 -- sk ∈ st) ∧ (addobj(r, class, fis, st) -- r)[r0 -- sk] = st[r0 -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ r ≠ r0 → (r -- sk ∈ addobj(r0, class1, fis, st) ↔ r -- sk ∈ st)
Proof step 17:
newref(r, st) ⊦ r = jvmref, (r0 -- sk ∈ st → r0 -- sk ∈ addobj(r, class, fis, st) -- r) ∧ (addobj(r, class, fis, st) -- r)[r0 -- sk] = st[r0 -- sk]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r -- sk ∈ st -- r0 ↔ r ≠ r0 ∧ r -- sk ∈ st])]]