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Proof step 2 from proof exactarray-addobj-01 (previous step)

is_referencevalue(val) ⊦ val .refval = r0, exactarray(val, ty, i, addobj(r0, class, fis, st)) ↔ exactarray(val, ty, i, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 1:
⊦ r ≠ r0 → (exactarray(refval(r), ty, i, addobj(r0, class, fis, st)) ↔ exactarray(refval(r), ty, i, st))

Rule argument

[speclemmaarg: ,is_referencevalue(val) → (r = val .refval ↔ val = refval(r)) ,[val, r] → [val, r] ,T ,javavalue , ,elim-13 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_referencevalue(val) → ( r = val .refval ↔ val = refval(r))])], [EXTRATERMS : (val, r)]]